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The value between 0 and 15 needs to be random and also wether its + or - needs to be random.

EDIT:

Hmm, after a bit of thought.

Code: Select all




int HP;


int value = (rand()%16);


int switch = (rand()%1);





if (switch==1) then


    {


        HP == (HP/100)*(100+value);


    }


    else


        {


         HP == (HP/100)*(100-value);


         }

I think that would work.

Grr, pissy CODE tags

Posted: Thu Oct 23, 2003 6:29 am Post subject:

((rand()%16)+1)

Posted: Thu Oct 23, 2003 6:47 am Post subject:

((rand()%30)-15)

Posted: Thu Oct 23, 2003 6:57 am Post subject:

Thanks demon, thats alot easier.

Posted: Thu Oct 23, 2003 7:05 am Post subject:

No idea if I got the syntax right or not. I know zip about C and C++. Smile

The method is sound, though, even if I muffed the syntax.

Posted: Thu Oct 23, 2003 7:12 am Post subject:

Yeah its good, It meant I could get rid of the -/+ switch that I had. Made my program a tinsy bit faster.

Now I just need to know why e_hp is getting assigned 0 after this:

Code: Select all

random_value = ((rand()%30)-15);


    while (random_value==0)


    {


          random_value = ((rand()%30)-15);


    }


      


    rand_att = (rand()%3);





         e_hp = (((base + (rand_att*5))/100)*(100+random_value));

Posted: Thu Oct 23, 2003 8:48 am Post subject:

I found out why, and a right tricky little bastard it was as well.

base is an int value, and I have it in a calculation with a division. I -think- C++ caste (?) the float (which is less than 1) into an int which turned it to 0. The rest of the calculation incloves the zero also. So the whole statement was zero.